1、通过循环进⾏删除
public static void removeDuplicate(List list) { for ( int i = 0 ; i < list.size() - 1 ; i ++ ) { for ( int j = list.size() - 1 ; j > i; j -- ) { if (list.get(j).equals(list.get(i))) { list.remove(j); } } }
System.out.println(list); }
2、通过HashSet删除
public static void removeDuplicate(List list) { HashSet h = new HashSet(list); list.clear(); list.addAll(h);
System.out.println(list); }
3、删除重复元素,并保持顺序。(我没试)
public static void removeDuplicateWithOrder(List list) { Set set = new HashSet();
List newList = new ArrayList();
for (Iterator iter = list.iterator(); iter.hasNext();) { Object element = iter.next(); if (set.add(element)) newList.add(element); }
list.clear();
list.addAll(newList);
System.out.println( \" remove duplicate \" + list); }
4、定义⼀个⽅法,调⽤即可。
publi List if(!list.contains(str)){ //查看新集合中是否有指定的元素,如果没有则加⼊list.add(str);}} return list; //返回集合} public class Test{ public static void main(String[] args){ ArrayList arr = getNewList(arr); //⽅法去重System.out.println(arr);}} 因篇幅问题不能全部显示,请点此查看更多更全内容